A quality control manager for a city transportation department wants to improve customer satisfaction. To assess the current customer satisfaction level, the manager counts the number of customer complaints for 30 days.
The manager performs a 1-sample Poisson rate test to determine whether the average rate of complaints per day is greater than 10.
The null hypothesis states that the rate is 10 complaints per day. Because the p-value of 0.000 is less than the significance level of 0.05 (denoted by α or alpha), the manager rejects the null hypothesis and concludes that the rate of complaints is greater than 10 per day.
λ: Poisson rate of Number of complaints |
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Exact method is used for this analysis. |
N | Total Occurrences | Sample Rate | 95% Lower Bound for λ |
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30 | 598 | 19.9333 | 18.6118 |
Null hypothesis | H₀: λ = 10 |
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Alternative hypothesis | H₁: λ > 10 |
P-Value |
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0.000 |