A chemist for a pharmaceutical company wants to determine whether the mean reaction time for a newly developed antacid is less than 12 minutes.
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The alternative hypothesis states that the mean reaction time is less than 12 minutes. Because the p-value is 0.203, which is greater than the significance level of 0.05, the chemist fails to reject the null hypothesis and cannot conclude that the mean reaction time is less than 12 minutes. The histogram shows that the bootstrap distribution appears to be normal, so the chemist can trust the results.
Variable | N | Mean | StDev | Variance | Sum | Minimum | Median | Maximum |
---|---|---|---|---|---|---|---|---|
Time | 16 | 11.331 | 3.115 | 9.702 | 181.300 | 7.700 | 10.050 | 16.000 |
Null hypothesis | H₀: μ = 12 |
---|---|
Alternative hypothesis | H₁: μ < 12 |
Number of Resamples | Mean | StDev | P-Value |
---|---|---|---|
1000 | 11.9783 | 0.7625 | 0.199 |