A scientist for a company that manufactures processed food wants to assess the percentage of fat in the company's bottled sauce. The advertised percentage is 15%. The scientist measures the percentage of fat in 20 random samples. Previous measurements found that the population standard deviation is 2.6%.

The scientist performs a 1-sample Z-test to determine whether the fat percentage differs from 15%.

From the drop-down list, select Sample data in a column.

In Sample, enter Percent Fat.

In Known standard deviation, enter 2.6.

Select Perform hypothesis test.

In Hypothesized mean, enter 15.

Click OK.

Interpret the results

The null hypothesis states that the mean of the percentage of fat equals 15%. Because the p-value is 0.012, which is less than the significance level of 0.05, the scientist rejects the null hypothesis. The results indicate that mean percentage of fat differs from 15%.

Descriptive Statistics

N

Mean

StDev

SE Mean

95% CI for μ

20

16.4600

2.2582

0.5814

(15.3205, 17.5995)

μ: mean of Percent Fat

Known standard deviation = 2.6

Test

Null hypothesis

H₀: μ = 15

Alternative hypothesis

H₁: μ ≠ 15

Z-Value

P-Value

2.51

0.0120

By using this site you agree to the use of cookies for analytics and personalized content. Read our policy